Vektorrechnung

Hallo Jann-Eve.

Test Überschrift

Test: Addition:

$\begin{align} L & = \lim_{|x| \to \infty}\ \frac{\cos \frac 1x \cdot \frac{-1}{x^2}}{\frac{-1}{x^2}}\\ & = \lim_{|x| \to \infty} {\cos\frac 1x} \cdot \frac{-1}{x^2} \cdot \frac{x^2}{-1}\\ & = \cos\frac 1{\infty} = \cos 0 = 1 \end{align}$

Formel (1)